Dansby Swanson, former Vanderbilt star, leaving Atlanta Braves for new MLB team, per report
Dansby Swanson, the No. 1 overall pick in the 2015 MLB Draft, former Vanderbilt second baseman/shortstop, College World Series champion and 2021 World Series Champion, is moving on from the Atlanta Braves after 7 years with the organization.
Swanson was a star his 2nd year with Vanderbilt and was named the Most Outstanding Player in Vanderbilt’s first CWS Championship in 2014. It was believed that he would be leaving Atlanta for a while now after becoming a free agent.
On Saturday, Swanson reportedly finalized a contract with the Chicago Cubs.
BREAKING: Shortstop Dansby Swanson and the Chicago Cubs are finalizing an agreement on a contract, sources tell ESPN.
— Jeff Passan (@JeffPassan) December 17, 2022
According to MLB Insider Russell Dorsey, Swanson will be taking a 7-year deal worth $177 million. This deal will include a no-trade clause, per his report.
Swanson’s deal is a seven-year deal worth $177 million and includes a full no-trade clause, sources tell @BallySports and @Stadium. https://t.co/0YOtXfToDq
— Russell Dorsey (@Russ_Dorsey1) December 17, 2022
Swanson won the World Series with the Braves in 2021, blasting a crucial home run into right field in Game 4 against the Astros to tie things up. Atlanta went on to win Game 4 and later defeat the Astros in 6 games.
